-(6/10)t^2+12t=0

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Solution for -(6/10)t^2+12t=0 equation: 



-(6/10)t^2+12t=0



Domain of the equation: 10)t^2!=0

t!=0/1

t!=0

t∈R



We add all the numbers together, and all the variables

-(+6/10)t^2+12t=0

We add all the numbers together, and all the variables

12t-(+6/10)t^2=0

We multiply all the terms by the denominator


12t*10)t^2-(+6=0

Wy multiply elements

120t^2+6=0

a = 120; b = 0; c = +6;
Δ = b2-4ac
Δ = 02-4·120·6
Δ = -2880
Delta is less than zero, so there is no solution for the equation

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